Age Problems( Week 30 Evaluation) 1. Two people have the same two digits for their ages but their ages are in reverse order with each other (i.e. if one is 19 years old, then the other is 91 years old). If the sum of the two digits is 6, and one person is 18 years older than the other, how old is the younger person? 2. The average age of 9 people is 22. None of them are younger than 16 years old. How old is the oldest possible age in the group? 3. Jennifer's age is a multiple of 3 this year. Next year it will be a multiple of 4. She is more than 4 years old. At least how old is she now? 4. Susan's age is of Richard's age this year. 1 year ago, her age was of Richard's age. How old is Susan now? 5. Jane's age is a multiple of 9 this year. Next year it will be a multiple of 7. At least how old is she now? 6. The sum of the ages of three brothers is 6. The oldest brother is 3 times as old as the youngest one. The ages of the two younger brothers differ by 1 year. What is the age of the brother in the middle? 7. Two people have the same two digits for their ages but their ages are in reverse order with each other (i.e. if one is 19 years old, then the other is 91 years old). If the sum of the two digits is 11, and one person is 27 years older than the other, how old is the older person? 8. Two people have two-digit ages. Both age numbers have a digit sum of 7 and an equal digit product. If one person is 9 years older than the other person, how old is the older person? 9. Julia is 3 times as old as Ed. Jane is 9 years older than Ed and 4 years younger than Ben. Jennifer is twice as old as Ed. If the sum of the 5 people's ages is 70, how old is Julia? 10. Julia is 4 times as old as Tom. However, 4 years later, she will only be twice as old as Tom. How old is Tom now? |